IFS Encyclopedia

Quaquaversal Tiling

Fractal dimension: 3

Visualization

Open in IFStile ↗
AIFS program
@
$dim=6
$subspace=[q,0,2,4]
a=[0,-1,0,0,0,0,1,0,0,0,0,0,0,0,1,0,0,0,0,0,0,0,-1,0,0,0,0,1,0,0,0,0,0,0,0,1]
b=[1,0,0,0,0,0,0,1/2,0,0,0,-3/2,0,0,1/2,0,3/2,0,0,0,0,1,0,0,0,0,-1/2,0,1/2,0,0,1/2,0,0,0,1/2]
q=[0,0,0,9,0,0,0,0,0,0,6,0,0,0,0,0,0,3,3,0,0,0,0,0,0,2,0,0,0,0,0,0,1,0,0,0]
h0=1*[1,0,0,0,0,1]
h1=1*[1,1,0,0,0,0]
h2=1*[0,0,0,0,0,1]
h3=a^3*[-1,1,0,0,0,0]
h4=a^3*b^3*[-1,-2,0,0,0,-1]
h5=a^2*b^3*[-1,0,0,0,0,-1]
h6=b^4*[0,-1,0,0,0,0]
h7=b^4*a^2*[-1,1,0,0,0,0]
A=2^-1*(h0|h1|h2|h3|h4|h5|h6|h7)*A

Overview

The quaquaversal tiling is a 3D aperiodic tiling introduced by John Conway and Charles Radin (1998) as the 3-dimensional analog of the pinwheel tiling. Its prototile is a 30-60-90 triangular prism that decomposes into 8 smaller congruent copies scaled by 1/21/2.

The defining property is orientational density in SO(3): the set of tile orientations that appear in the tiling is dense in the full rotation group SO(3)SO(3). No rotational or translational symmetry of the tiling exists.

Algebraic Structure

The construction lives in a 6-dimensional rational space Q6\mathbb{Q}^6. Two rotation matrices aa (order 4, 90° rotation) and bb (order 6, 60° rotation) generate the dense subgroup G(6,4)SO(3)G(6,4) \subset SO(3):

a4=I,b6=Ia^4 = I, \quad b^6 = I

The rendering projection is given by an explicit 6×66\times 6 matrix qq that selects the three eigenplanes corresponding to rendering indices 0, 2, 4 (AIFS: $subspace=[q,0,2,4] produces a 3D rendering).

The 8 maps are isometries from a,b\langle a, b \rangle composed with integer translations in Q6\mathbb{Q}^6, all contracting by 12\frac{1}{2}:

MapIsometryTranslation
h0h_0id\mathrm{id}[1,0,0,0,0,1][1,0,0,0,0,1]
h1h_1id\mathrm{id}[1,1,0,0,0,0][1,1,0,0,0,0]
h2h_2id\mathrm{id}[0,0,0,0,0,1][0,0,0,0,0,1]
h3h_3a3a^3[1,1,0,0,0,0][-1,1,0,0,0,0]
h4h_4a3b3a^3 b^3[1,2,0,0,0,1][-1,-2,0,0,0,-1]
h5h_5a2b3a^2 b^3[1,0,0,0,0,1][-1,0,0,0,0,-1]
h6h_6b4b^4[0,1,0,0,0,0][0,-1,0,0,0,0]
h7h_7b4a2b^4 a^2[1,1,0,0,0,0][-1,1,0,0,0,0]

The IFS equation is:

A=12(h0h1h2h3h4h5h6h7)(A)A = \tfrac{1}{2}(h_0 \cup h_1 \cup h_2 \cup h_3 \cup h_4 \cup h_5 \cup h_6 \cup h_7)(A)

Properties

References

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